Question

(1) Find the sum of all two digit natural numbers which are divisible by 4.​

Answer 1

Answer:

1188

Step-by-step explanation:

The numbers are $12, 16, 20 \dots 96$.

We have to find the sum.

Using sum of A.P. $\frac{n}{2} (2a+(n-1)d)$,         [$n=22$, $a=12$, $d=4$]

$Sum=\frac{22}{2} (2*12+(22-1)*4)$

$=11(24+84)$

$=108*11$

$=1188$

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