Question

1. Find the sum of first 10 multiples of '4'.​

Answer 1

Answer:

hope it is helpful to you....

Answer 2

First 10 multiples of 4 are:–

4, 8, 12, 16, 20, 24, 28, 32, 36, 40

So, a = 4

l {Last term} = 40

d = 4

n = 10

So,

S10 =

$\frac{n}{2 \times (a + l)}$

$= \frac{10}{2 \times (4 + 40)}$

$= 5 \times 44$

$= 220$

Hope it helps! ♡