Question

1)Find the sum of first 1000 positive integers.
please give some step by step answer it means a lot to me ​

Answer 1

formula n(n+1)/2

just substitute n= 1000

1000(1000+1)/2

1000*1001/2

500*1001

500500 final answer

Answer 2

Answer:

500500

Step-by-step explanation:

To find out the answer, we must apply the formula, $\frac{n(n+1)}2$

Over here, n = the number of integers, which in this case is 1000.

Now lets apply the formula and solve the question:

$\frac{n(n+1)}2$ = $\frac{1000(1000+1)}2$

         = $\frac{1000(10001)}2$

         = ${500*1001}$                       - I have cancelled 2 and 1000

         = 500500

Thus, the sum of the 1st 1000 positive integers are 500500

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Hope it helps

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