Question

1. Find the sum of following APs :
(1)2, 7, 12, ..., to 10 terms.
( 2 ) -37, -33, -29, ..., to 12 terms
(3)0.6, 1.7, 2.8, ..., to 100 terms.
1
1
1
to 11 terms.
(4)
9
15
12
10​

Answer 1

Step-by-step explanation:

1. 2, 7, 12,.........

here

First term, a = 2

common difference, d = 7 - 2 = 5

number of terms, n = 10

so required sum =

$\frac{n}{2} (2a \: + (n - 1)d) \\ = \frac{10}{2} (2 \times 2 + 9 \times 5) \\ = 5 \times 49 \\ = 245$

Rest parts are similarly solved

Answer 2

Answer:

4th is not clear

Step-by-step explanation:

rest of the answers are in photo...