1. Find the sum of the following APs:. 0.6, 1.7,2.8,..., to 100 terms.
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Answer:
5465
Step-by-step explanation:
Let the first term of the given AP be a1 and d be the common difference.
Then, a1=0.6 , n=100 , d=1.7-0.6= 1.1
Since, we know that the sum of term of an AP is
Sn = n/2[2a+(n-1)d]
=> = 100/2 {2(0.6) + (100-1)1.1}
=> = 50 { 1.2 + 99(1.1)}
=> = 50 (1.2+108.1)
=> = 50 (109.3)
=> = 5465
Hence, the sum of 100 terms of the given AP is 5465.
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