Question

1. Find the sum of the following APs:. 0.6, 1.7,2.8,..., to 100 terms.​

Answer 1

Answer:

5465

Step-by-step explanation:

Let the first term of the given AP be a1 and d be the common difference.

Then, a1=0.6  ,  n=100   ,   d=1.7-0.6= 1.1

Since, we know that the sum of $n^{th}$ term of an AP is

         Sn = n/2[2a+(n-1)d]

=>            = 100/2 {2(0.6) + (100-1)1.1}

=>            = 50 { 1.2 + 99(1.1)}

=>            = 50 (1.2+108.1)

=>            = 50 (109.3)

=>            = 5465

Hence, the sum of 100 terms of the given AP is 5465.

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