Question

1. Find the sum of the following APs:
(1) 2,7, 12, ..., to 10 terms.​

Answer 1

Answer:

S10=

$\frac{n}{2} (2a + (n - 1)d) \\ = \frac{10}{2} (2 \times 2 + 9 \times 5) \\ = 5(4 + 45) \\ = 5 \times 49$

= 245

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