Question

1. Find the surface area and volume of a cuboid of length 6m, breadth 3m and height
2.5m.​

Answer 1

Answer:

Formulas to be remembered:

• Volume of a Cuboid = Length × Breadth × Height
• Total Surface Area of Cuboid = 2 ( lb + bh + hl )

Since the question does not specify the type of surface area, it is generally assumed as Total Surface Area.

Given dimensions:

• Length ( l ) = 6m
• Breadth ( b ) = 3 m
• Height ( h ) = 2.5 m

1. Volume of Cuboid = lbh

⇒ Volume of Cuboid = 6 m × 3 m × 2.5 m

⇒ Volume of Cuboid = 45 m³

2. Total Surface Area = 2 ( lb + bh + hl )

⇒ TSA of Cuboid = 2 ( 6 × 3 + 3 × 2.5 + 2.5 × 6 )

⇒ TSA of Cuboid = 2 ( 18 + 7.5 + 15 )

⇒ TSA of Cuboid = 2 ( 40.5 )

⇒ TSA of Cuboid = 81 m²

Therefore the total surface area of the given cuboid is 81 m² and the volume of the cuboid is 45 m²

Answer 2

Answer:

${\boxed{\rm{Volume=45\:{m}^{3}}}}$

${\boxed{\rm{Surface\:area=81\:{m}^{2}}}}$

________________________

$\bf {Given}\begin{cases} \sf {Length = 6\:m}\\\sf{Breadth=3\:m} \\\sf{Height=2.5\:m} \end{cases}$

Formula used:-

${\boxed{\sf{Volume\:of\:cuboid=Length\times Breadth \times Height}}}$

${\boxed{\sf{Surface\:area=2(ab+bc+ca) }}}$

Firstly,

$\sf Volume = (6\times 3 \times 2.5)\:{m}^{3}$

$\rightarrow{\boxed{\sf{Volume = 45\:{m}^{3}}}}$

$\therefore\bold{\underline{Volume\:of\:cuboid=45\:{m}^{3}}}$

_________________________

Secondly,

$\sf Surface\:area=2(6\times 3 \: + 3 \times 2.5 \: + 2.5 \times 6)\:{m}^{2} \\\\\rightarrow\sf Surface\:area = (2 \times 40.5)\:{m}^{2}$

$\rightarrow{\boxed{\sf {Surface\:area = 81\:{m}^{2}}}}$

$\therefore\bold{\underline{Surface\:area=81\:{m}^{2}}}$