Question

1 Find the third term of the pythagorian triplet if two terms are 10 and 26.​

Answer 1

Answer:

26²=10²+x²

676-100=x²

576=x²

x=24

Step-by-step explanation:

Answer 2

Answer:

According to Pythagorean theorem-

${h}^{2} = {p}^{2} + {b}^{2} \\ {26}^{2} = {10}^{2} + x \\ {26}^{2} - {10}^{2} = {x}^{2} \\ 676 - 100 = {x}^{2} \\ 576 = {x}^{2} \\ {</strong><strong>2</strong><strong>4}^{2} = {x}^{2} \\ </strong><strong>2</strong><strong>4 = x$

Therefore the third Pythagorean triplet = 24