Math, asked by StudyLearn786, 3 months ago

1. Find the value of 3X -4Y - 2Z when :
X = 3x - 7x² - 9x + 7, Y = 12x + 3x - 13x +1 and Z = 6x° - 5x² - 6x + 4

I need Whole Solution Plz Give Me ​

Answers

Answered by renukaparmar2709
0

Answer:

-11x²-14x-3

Step-by-step explanation:

X= 3x-7x²-9x+7 = -7x²+3x-9x+7 = -7x²-6x+7

Y= 12x+3x-13x+1 = 2x+1

Z= 6x°-5x²-6x+4 = 6(1)-5x²-6x+4 = -5x²-6x+4+6 = -5x²-6x+10

Substitute the values

3X-4Y-2Z

3 [ -7x²-6x+7] -4 [2x+1] -2 [-5x²-6x+10]

-21x² -18x +21 -8x -4 +10x² +12x -20

Get the like terms together

-21x² +10x² -18x -8x +12x +21 -4 -20 =

-11x²-14x-3

Answered by prititalukdar04
0

3X = 3 (3x-7x²-9x+7)

= 9x-21x²-27x+21

= 21x²+18x-21

-4Y = -4 (12x+3x-13x+1)

= -4 (2x+1)

= -8x-4

-2Z = -2 (6x°-5x²-6x+4)

= -2 (6-5x²-6x+4)

= -2 (-5x²-6x+10)

= 10x²+12x-20

therefore,

3X-4Y-2Z= 21x²+18x-21-8x-4+10x²+12x-20

= 21x²+10x²+18x-8x+12x-21-4-20

= 31x²+22x-45

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