1. Find the value of 3X -4Y - 2Z when :
X = 3x - 7x² - 9x + 7, Y = 12x + 3x - 13x +1 and Z = 6x° - 5x² - 6x + 4
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Answers
Answered by
0
Answer:
-11x²-14x-3
Step-by-step explanation:
X= 3x-7x²-9x+7 = -7x²+3x-9x+7 = -7x²-6x+7
Y= 12x+3x-13x+1 = 2x+1
Z= 6x°-5x²-6x+4 = 6(1)-5x²-6x+4 = -5x²-6x+4+6 = -5x²-6x+10
Substitute the values
3X-4Y-2Z
3 [ -7x²-6x+7] -4 [2x+1] -2 [-5x²-6x+10]
-21x² -18x +21 -8x -4 +10x² +12x -20
Get the like terms together
-21x² +10x² -18x -8x +12x +21 -4 -20 =
-11x²-14x-3
Answered by
0
3X = 3 (3x-7x²-9x+7)
= 9x-21x²-27x+21
= 21x²+18x-21
-4Y = -4 (12x+3x-13x+1)
= -4 (2x+1)
= -8x-4
-2Z = -2 (6x°-5x²-6x+4)
= -2 (6-5x²-6x+4)
= -2 (-5x²-6x+10)
= 10x²+12x-20
therefore,
3X-4Y-2Z= 21x²+18x-21-8x-4+10x²+12x-20
= 21x²+10x²+18x-8x+12x-21-4-20
= 31x²+22x-45
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