Question

1. Find the value of:
a^2 + b^2 when a + b = 9, ab = 20​

Answer 1

Answer:

Step-by-step explanation:

we know ,

$(a+b)^{2} = a^{2} +b^{2} + 2ab$

so,

81 = $a^{2} +b^{2}$ + 40

a^2 + b^2 = 81-40

= 41

Thanks!

Answer 2

Answer:

given,

a+b=9

ab=20

a²+b²+2ab-2ab

(a+b)²-2ab

9²-2*20

81-40

41

therefore,

the answer is 41

Step-by-step explanation:

hope it helps yrr