Question

1. Find the value of acceleration due to gravity on a star whose mass is 3 x 10^30 kg and radius is 1.8 x 10^8 m. Given G = 6.67 x 10^-11 N m² kg^-2.​

Answer 1

Answer:

6.177 × 10³ m/s²

Explanation:

$g = \frac{GM}{R^{2}}</p><p> \\ = \frac{6.67 \times {10}^{ - 11} \: n {m}^{2})kg \times 3 \times {10}^{30} \: kg }{(1.8 \times {10}^{8})^{2} m }\\= \frac{6.67 \times 3 \times {10}^{19} }{3624 \times {10}^{16} } \\ = \frac{667}{108} \times 10 ^{3} \\ = 6.177 \times {10}^{3} \: m) {s}^{2}$