Math, asked by saifposharkar, 3 months ago

(1) Find the value of b2 - 4ac, if a =2, b= -8, c=5.​

Answers

Answered by hukam0685
1

The value of discriminant \bf b^2-4ac is 24.

Given:

  • a =2, b= -8, c=5.

To find:

  • Find the value of b²-4ac.

Solution:

Put the values of a,b and c in discriminant.

D=(-8)^2-4(2)(5)\\

or

D=64-40\\

or

\bf D=24\\

Thus,

Value of discriminant is 24.

Extra information:

We can find nature of roots of quadratic equation on the basis of discriminant.

here D>0

Thus,

We can say that roots of quadratic equation are real and distinct.

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Answered by preeti353615
3

Answer:

If a =2, b= -8, c=5 then b² - 4ac is 24.

Step-by-step explanation:

Given: a = 2, b = -8 and c = 5

Find b^2 - 4ac

Put value in b² - 4ac

= (-8)² - 4 (2)(5)

Square of negative number is always positive.

= 64 - 8 (5)

= 64 - 40

= 24

So, value of b² - 4ac is 24.

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