Question

1) find the value of determinant of the following 2y2-y+2​

Answer 1

Step-by-step explanation:

Question

find the value of determinant of the following 2y2-y+2

Solution

$2y {}^{2} - y + 2 = 0$

For a Quadratic Equations ,

$ax {}^{2} + bx + c = 0 \: D = b { }^{2} - 4ac$

Here ,

$a = 2,b = - 1,c = 2$

$D = ( - 1 ) {}^{2} - 4 \times 2 \times 2 = 1 - 16 = - 15$