Question

1) Find the value of f(x) = 3x - 5x + 3 at x = -2
2) If P(x) = x2 + 3x2 - 2x + 4, find the value of P (-2) + P (1)+P (0)
3) Find the value of a, if (x-1) is a factor of 2x² + ax + V2
4) Without actually calculating the cubes; find the value
5) If x2 + 3 = 146, find the value of x -
6) Expand (x - x + 2)?
LEVEL: 2
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Answer 1

Answer:

f(-2)=3(-2)-5(-2)+3

=-1+10-6

=9-6

=3

Answer 2

Step-by-step explanation:

1. if x=-2 then put value in the given equation

f(-2)=3(-2)-5(-2)+3

f(-2)=-6+10+3

f(-2)=7

3. if (x-1) then by comparing by x-a

so (x-1) become x=1,

now put value in 2x²+ax +x²

p(x)= 2(1)² +a(1)+(1)²

p(x)= 2 +a +1

p(x)= 3+a=

a=-3

5.x²+3=146

x²=146-2

x²=144

x=√144

x=12