1. Find the value of :
(i) sin 30° cos 30°
(ü) tan 30° tan 60°
(iii) cos2 60° + sin? 30°
(iv) cosec2 60° - tan2 30°
(v) sina 30° + cos2 30° + cot2 45°
(vi) cos2 60° + sec2 30° + tan2 45°
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Answered by
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Answer:
In the table π=180°
π/6=30 π/4=45 π/3=60 π/2=90
Step-by-step explanation:
Substitute the above values you will get
1)sin30°cos30°=(1/2)(√3/2)=√3/4
2)tan30°tan60°=(1/√3)(√3)=1
3)cos^2(60°)+sin^2(30°)=1
4)csc^2(60°)-tan^2(30)=1
5)sin^2(30)+cos^2(30)+cot^2(45)=1+1=2
6)cos^2(60)+sec^2(30)+tan^2(45)=19/12
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Answered by
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(i) sin 30° cos 30°
» 1/2 × √3/2
» √3/4
(ü) tan 30° tan 60°
» 1/√3 × √3
» 1
(iii) cos² 60° + sin² 30°
» 1/2² + 1/2²
» 1/4 + 1/4
» 1/2
(iv) cosec² 60° - tan² 30°
» √3²/2² - 1/√3²
» 3/4 - 1/3
» 5/12
(v) sin² 30° + cos² 30° + cot² 45°
» 1/2² + √3²/2² + 1
» 1/4 + 3/4 + 1
» 8/4
» 2
(vi) cos² 60° + sec² 30° + tan² 45°
» 1/2² + 2²/√3² + 1
» 1/4 + 4/3 + 1
» 31/12
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