Math, asked by amrita4360, 6 months ago

1. Find the value of :
(i) sin 30° cos 30°
(ü) tan 30° tan 60°
(iii) cos2 60° + sin? 30°
(iv) cosec2 60° - tan2 30°
(v) sina 30° + cos2 30° + cot2 45°
(vi) cos2 60° + sec2 30° + tan2 45°





Please give the correct answer. The person who will give the correct answer will be marked as brainliest. Plz help me​

Answers

Answered by sathyamargerate0410
1

Answer:

In the table π=180°

π/6=30 π/4=45 π/3=60 π/2=90

Step-by-step explanation:

Substitute the above values you will get

1)sin30°cos30°=(1/2)(√3/2)=√3/4

2)tan30°tan60°=(1/√3)(√3)=1

3)cos^2(60°)+sin^2(30°)=1

4)csc^2(60°)-tan^2(30)=1

5)sin^2(30)+cos^2(30)+cot^2(45)=1+1=2

6)cos^2(60)+sec^2(30)+tan^2(45)=19/12

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Attachments:
Answered by Anonymous
4

(i) sin 30° cos 30°

» 1/2 × √3/2

» √3/4

(ü) tan 30° tan 60°

» 1/√3 × √3

» 1

(iii) cos² 60° + sin² 30°

» 1/2² + 1/2²

» 1/4 + 1/4

» 1/2

(iv) cosec² 60° - tan² 30°

» √3²/2² - 1/√3²

» 3/4 - 1/3

» 5/12

(v) sin² 30° + cos² 30° + cot² 45°

» 1/2² + √3²/2² + 1

» 1/4 + 3/4 + 1

» 8/4

» 2

(vi) cos² 60° + sec² 30° + tan² 45°

» 1/2² + 2²/√3² + 1

» 1/4 + 4/3 + 1

» 31/12

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