1. Find the value of k for which the polynomial y 3 - 3y 2 + 3y + k has 3 as its zero.
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Let 3 is one of the zero of polynomial p(x) = y³-3y²+3y+k .
i.e. P(x) = y³-3y²-3y+k = 0
P(3) = (3)³-3(3)²+3(3)+k = 0
= 27-3(9)+9+k = 0
= 27-27+9+k = 0
= 9+k = 0
= k = -9
i.e. k = -9
Therefore, required value of k is -9.
Please select it brainliest answer.
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Answer:
Let 3 is one of the zero of polynomial p(x) = y³-3y²+3y+k .
i.e. P(x) = y³-3y²-3y+k = 0
P(3) = (3)³-3(3)²+3(3)+k = 0
= 27-3(9)+9+k = 0
= 27-27+9+k = 0
= 9+k = 0
= k = -9
i.e. k = -9
Therefore, required value of k is -9.
Please select it brainliest answer.
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