1. Find the value of k for which the quadratic
equation 4x 2 – 3kx + 1 = 0 has two real and equal
roots.
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Step-by-step explanation:
a = 4, b = -3k , c = 1
b^2 - 4ac = 0
(-3k)^2 - 4 (4)(1) = 0
9k^2 = 16
k^2 = 16/9
k = +/- 4/3
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