Question

1. Find the value of k for which the system of equations 2x+3y=7

and 8x+ (k+4)y-28=0 has infinitely many solution.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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Answer:

k=8

Step-by-step explanation:

2x+3y=7.....(1)

8x+(k+4)y=28....(2)

let equation (1)×4 ;

8x+12y=28

8x+(k+4)y=28

-. -. -

_______________

12y-(k+4)y=0

12y=(k+4)y

then k=8