Question

1.
Find the  value of k , if one of the zeroes of a quadratic polynomial 
(1 Point)
(−1)2++1  −3 , (k−1)x2+kx+1 is −3 , ​

Answer 1

Answer:

Given −3 is the zero of the polynomial (k−1)x

2

+kx+1

So −3 must satisfy the equation (k−1)x

2

+kx+1=0

⟹(k−1)(−3)

2

+k(−3)+1=0

⟹9(k−1)−3k+1=0

⟹9k−9−3k+1=0

⟹6k=8

⟹k=

3

4

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Answer 2

Answer:

-1×2+(+1)-3= 0

(K-1)×2+Kx+1 IS -3

VALUE OF K IS=2

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