Question

1. Find the value of K if the equation x2- 2(k+1)x+k2 = 0 has equal root​

Answer 1

Answer:

D=b^2-4ac

4(k+1) ^2-4x1x2k

4(k^2+1+2k) -8k=0

for equal roots discriminate value equals to 0

4k^2+4+8k-8k=0

k^2=-1

k=√-1