1. Find the value of k so that the following system of equations has no solution:
3x - y - 5 =0
6x - 2y + k= 0
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Step-by-step explanation:
The given system of equations: 3x - y - 5 = 0 ….
(i) And, 6x - 2y + k = 0 ….
(ii) These equations are of the following form: a1x+b1y+c1 = 0,
a2x+b2y+c2 = 0
where, a1 = 3, b1= -1, c1 = -5
and a2 = 6, b2 = -2, c2 = k
In order that the given system has no solution, we must have: Hence,
equations (i) and (ii) will have no solution if k ≠ -10.
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