Question

1. Find the value of k so that the following system of equations has no solution:
3x - y - 5 =0
6x - 2y + k= 0​

Answer 1

Step-by-step explanation:

The given system of equations: 3x - y - 5 = 0 ….

(i) And, 6x - 2y + k = 0 ….

(ii) These equations are of the following form: a1x+b1y+c1 = 0,

a2x+b2y+c2 = 0

where, a1 = 3, b1= -1, c1 = -5

and a2 = 6, b2 = -2, c2 = k

In order that the given system has no solution, we must have: Hence,

equations (i) and (ii) will have no solution if k ≠ -10.