Question

1 Find the value of n if (2/3)³ ×(2/3)⁵ = [2/3]n-²​

Answer 1

Answer:

( 2 / 3 )³ × ( 2 / 3 )⁵ = ( 2/ 3 )n-²

(2 / 3 )³+⁵ = ( 2/ 3) n-²

( 2/3)⁸ = (2/3) n-²

(2/3)⁸+² = ( 2/3 )n

( 2/3)¹⁰ = (2/3)n ( 2/3, 2/3 wil cancel out)

10 = n ans :)