Question

1) Find the value of the constant k
so that the function f defined below
is continous at x = 0, where
f(x)
=
1- cos 4x/8x^2, when x not equal to 0
,k,when x=0​

Answer 1

Answer:

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Step-by-step explanation:

In the function,

We have been provided that,

where, x is not equal to 0.

Now,

For solving the given function we have to solve this using the trigonometric identity,

cos4x = cos²2x - sin²2x

also,

sin²2x + cos²2x = 1

So,

On putting these values in the function we get,

Now, as the conditions are given for the limit on the function, we can say that,

That's why the value of the function is a constant.

f(x) = 1 = constant

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