Question

1. Find the value of the expression 3x + 5 (x – 2) for x = 2
2. Find the value of the expression x^2 + 2x + 1 for x = – 1
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Answer 1

Answer:

• Ans. 1) 6
• Ans. 2) 0

Step-by-step explanation:

Solution :

Answer 1)

$\sf{Solution\:of\:3x + 5(x - 2)\:for\:x = 2}$

Substitute the value of x in the given expression:

$\sf\longrightarrow \: {3x + 5(x - 2)}$

$\sf\longrightarrow \:3(2)+ 5(2 - 2)$

$\sf\longrightarrow \:6 + 5(0)$

$\sf\longrightarrow \:6 + 0$

$\sf\longrightarrow \:6$

Therefore, the solution of $\sf{3x + 5(x - 2)}$ for $\sf{x = 2}$ is 6.

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Answer 2)

$\sf{Solution\:of\:x^{2} + 2x +1\:for\:x = (-1)}$

Substitute the value of x in the given expression:

$\sf{\longrightarrow} \: x^{2} + 2x + 1$

$\sf{\longrightarrow} \: {( - 1)}^{2} + 2( -1 ) + 1$

$\sf{\longrightarrow} \: 1 - 2 + 1$

$\sf{\longrightarrow} \: - 1 - 1$

$\sf{\longrightarrow} \: 0$

Therefore, the solution of $\sf{x^{2} + 2x +1}$ for $\sf{x =(-1)}$ is 0.

Answer 2

$\huge \bf Answer \: 1$

3x + 5 (x - 2)

•x = 2

3(2) + 5 (2 - 2)

6 + 5 × 0

Any number multiplied by 0 is 0

6 + 0

$\fbox {Ans. = 6}$

$\huge \bf Answer \: 2$

x² + 2x + 1

•x = -1

-1² + 2(-1) + 1

1 - 2 + 1

1 + 1 - 2

2 - 2

$\fbox {Ans. = 0}$