Question

1 find the value of x and y . x+3y = 22 and x+7y=35​​

Answer 1

Answer:

Answer given in attachment

x is 49

y is 13/4

Answer 2

x + 3y = 22

x + 7y = 35

subtract equation 1 from equation 2

4y = 13

y = 13 / 4

we know that x + 3y = 22

substitute y value in first equation

x + 3 ( 13 / 4 ) = 22

x + 36 / 4 = 22

x = 22 - (36/4)

x = 52 /4

x = 13

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