Question

1.find the value of x if (6^0+4^-1)2^2=5^x.
2. Evaluate:-
(1^2+2^2+3^2+4^2)^-4.​

Answer 1

Answer:

1

Step-by-step explanation:

lhs

6^0=1

4^-1 =1/4

(1+1/4)2^2 = 5/4*4= 5

rhs= 5^x

so x= 1