Question

1) Find the value of x in the following figure. х 90 130 CU
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Answer 1

Answer:

(i) In figure (i) BOC is a straight line

\angle AOC+\angle AOB=180°

75° + 2x+ 65° +3x+x= 360°

5x+95° = 180°

5x= 180° - 95° =85°

x=\frac{85}{5}=17°

x= 17°

(ii) In figure (ii) angles are on a point

The sum = 360°

75° + 2x + 65° + x = 360°

6x+140° = 360°

6x= 360° - 140° =220°

x=\frac{220}{6}=\frac{110}{3}

x=\left(36\frac{2}{3}\right)°

x=36\frac{2}{3}

(iii) In figure (iii) angles are on a point

Their sum= 360°

5x+3x+40° +120° =360°

x=\frac{200}{8}=25°

x=25°

Answer 2

Answer:

40 degree please follow