Question

1. Find the value(s) of k, if one of the zeroes of the polynomial f(x) = (k^2+ 8)x^2 + 13x + 6k is reciprocal of the other. (a) 2,4 (b) 3,5 (c) 1,3 (d) -1,1​

Answer 1

Answer:

a is the answer the zeroes will be 2 and 4

when we do product of zeroes than

alpha into one upon alpha =6k/k^2+8

so it will be

1=6k/k^2+8

= k^2-6k+8

=k^2-4k-2k+8

=k(k-4) -2(k-4)

=(k-2)(k-4)

k=2,4

mark me brain least.