Question

1. Find the values of a and b for which the simultaneous equat
x + 2y = 1 and (a - b)x + (a + b)y = a +b-2 have infinitely many
solutions.​

Answer 1

Step-by-step explanation:

 x+2y=1 and (a-b)x+(a+b)y=a+b-2

Step-by-step explanation:

Correction in Question   (a+b)x+(a+b)y=a+b-2 should be  (a-b)x+(a+b)y=a+b-2

x + 2y = 1

(a-b)x + (a+b)y = a + b - 2

for infinite solution

1/(a - b)  =  2/(a + b)  = 1/(a + b - 2)

a +  b = 2a - 2b

=> a = 3b

2/(a + b) =  1/(a + b - 2)

=> 2a + 2b - 4  = a + b

=> a + b = 4

=> 3b + b = 4

=> 4b = 4

=> b = 1

=> a = 3

(a-b)x+(a+b)y=a+b-2

=> 2x + 4y = 2

=> x + 2y = 1

hope it will help you