Question

1. Find the values of x for which the distance between the points P (2, -3) and Q. (x, 5) is 10.​

Answer 1

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Answer 2

Answer:

$\sqrt{ (x - 2) {}^{2} + (5 - ( - 3)) {}^{2} } = {10}$

$(x - 2) {}^{2} + {8}^{2} = 10 {}^{2}$

$(x - 2) {}^{2} + 64 = 100$

$(x^{2} - 4x + 4) = 36$

${x}^{2} - 4x - 32 = 0$

${x}^{2} - 8x \: + 4x \: - 32 = 0$

x(x-8) + 4(x-8) = 0

(x-8)(x+4) = 0

x-8 = 0 or x+4 = 0

x = 8 or x = -4

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