Question

1. Find the volume, lateral surface area and the total surface area of the cuboid whose
length = 48 cm, breadth = 6 dm and height = 1 m​

Answer 1

Answer:

l = 48 cm, b = 6 dm = 60 cm, h = 1 m = 100 cm

Volume = lbh = 48 * 60 * 100 cm^3 = 288000 cm^3

LSA = (l+b)h = 108 * 100 = 10800 cm^2

TSA = lh + bh + lb = 48*60 + 60*100 + 48*100 = 2880 + 6000 + 4800

                                                                           = 13680 cm^2

Answer 2

261 m²

Solution ⚡

Given Length = 48cm = 0.48m

Breadth = 6.d.m. = 0.6m and height = 1m

We know that volume of cuboid =length

× breadth × height

so,

V = (0.48 x 0.6 x 1)

V = 0.288 m³

We know that total surface area of cuboid =

2 (Lb + bh + hl )

so,

surface area

= 2(0.48 × 0.6 + 0.6 x 1+1 x 0.48) Surface area = 2.288 + 0.6 + 0.48)

Total Surface area = 2.736 m2

We know that lateral area of cuboid

= 2[(1+ b) x h]

So,

Lateral surface area

= 2[(0.48 + 0.6) x 1] = Lateral surface area = 261 m2