1. Find the zeroes of the following quadratic polynomials and verify the relationship between
the zeroes and the coefficients
3x²-x-4
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Answer:
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Step-by-step explanation:
let p(x)=
3x²-x-4
=3x2-(4-3)x-4
=3x²-4x+3x-4
=x(3x-4)+1(3x-4)
=(x+1)(3x-4)
p(x)=0
(x+1)(3x-4)=0
if x+1=0
x=-1
if 3x-4=0
x=4/3
since zeroes=-1,4/3
sum of zeroes=-1+4/3=1/3=-coefficiant of x/COFFICIANT OF x²
product of zeroes=-1*4/3=-4/3=constant term/coefficient of x²
hope this helps you
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