(1)Find the zeroes of the given polynomials.
(i) p(x) = 3x
(ii) p(x) = xpower2 + 5x + 6
(iii) p(x) = (x+2)(x+3)
(iv) p(x) = x power4 - 16
(2)Draw the graphs of the given polynomial and find the zeroes. Justify the answers.
(i) P(x) = xpower2 - x - 12
(ii) p(x) = xpower2 - 6x + 9
(iii) p(x) = xpower2 - 4x + 5
(iv) p(x) = xpower2 + 3x – 4
(v) p(x) = xpower2 - 1
Answers
Answered by
0
Answer:
- 0
- -2,-3
- -3,-2
- 2
hope this will help u
Answered by
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(1)
(i) p(x) = 3x
3x = 0 => x = (-3)
(ii) p(x) = x^2 + 5x +6
= x^2 + 2x + 3x +6
= x(x+2) + 3(x+2)
= (x+3) (x+2)
p(x) = (x+3) (x+2)
(x+3)(x+2) = 0 => x = (-1)
(iii) p(x) = (x+2)(x+3)
(x+2)(x+3) = 0 => x = (-1)
I hope this will help you..
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