Question

1. Find the zeroes of the polynomial f(x) = x2 – 2 and verify the relation
between its zeroes and coefficients.
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Answer 1

Answer:

see the solution photo

Step-by-step explanation:

plus minus √2

Answer 2

Answer:

Step-by-step explanation:

We have,

f(x)=x²−2 ,

=x²(√2)²,

(x-√2)(x+√2),

The zeroes of(x) are given by f(x)=0 ,

(x−√2)(x+√2)=0,

(x-√2)=0 or (x+√2)=0,

x=√2 or x=-√2,

Thus ,the zeroes of f(x) are α=√2 and β=−√2,

Now,

Sum of the zeroes=α+β=√2+(-√2),

=0,

and , -(coefficient of x/coefficient x²),

=-(0/1),

=0,

Therefore sum of the zeroes=−(Coefficient x/coefficient x²),

Product of the zeroes=α×β=√2×-√2=-2,

and,(constant term/coefficient x²),

=-2/1,

=-2,

Therefore, product of zeros =(constant term/coefficient x²),

HOPE IT HELPS.