Question

1. Find the zeroes of the quadrate polynomial5 x square + 8 x minus 4 and verify the relationship between the zeros and the coefficients of the polynomials

Answer 1

Step-by-step explanation:

Polynomial: 5x² + 8x - 4

For the zeros of the Polynomial:

5x² + 8x - 4 = 0

5x² + 10x - 2x - 4 = 0

5x (x + 2) - 2 (x + 2) = 0

(x + 2) (5x - 2) = 0

So, x = -2, 2/5

Relation between the zeros and the coefficients of the Polynomial:

$x \: = \: - 2 = \: \alpha \\ x \: = \: 2 \div 5 \: = \: \beta \\ \\ \alpha + \beta \: = \: - b \div a \\ \alpha + \beta \: = \: - 8 \div 5 \\ - 2 \: + \: 2 \div 5 \: = \: - 8 \div 5 \\ (- 10 \: + \: 2) \div 5 \: = \: - 8 \div 5 \\ - 8 \div 5 \: = \: - 8 \div 5 \\ Similarly\\ \alpha \beta \: = \: c \div a \\ ( - 2) \times (2 \div 5) \: = \: ( - 4) \div 5 \\ (- 4 \div 5) \: = \: (- 4 \div 5) \\ Hence \: Proved$

Thanks! ✨

Answer 2

Answer:

plz mark me brillient

Step-by-step explanation:

Step-by-step explanation:

Polynomial: 5x² + 8x - 4

For the zeros of the Polynomial:

5x² + 8x - 4 = 0

5x² + 10x - 2x - 4 = 0

5x (x + 2) - 2 (x + 2) = 0

(x + 2) (5x - 2) = 0

So, x = -2, 2/5