Question

1) Find the zeroes of the quadratic polynomial : 3x² -75 and Find a quadratic polynomial of given numbers as the sum and product of zeroes respectively: (4,1)​

Answer 1

Answer:

3x ^{2}  - 75 = 0

3(x ^{2}  - 25) = 0

3((x) ^{2}  - (5) ^{2} ) = 0

3(x + 5)(x  - 5) = 0

(x + 5)(x - 5) = 0

either

x + 5 = 0

x =  - 5

or

x -5  = 0

x = 5

verification

sum \:  \: of \:  \: zeroes \:  \:  =  \frac{ - b}{a}  

5 + ( - 5) =  \frac{0}{3}  

0 = 0  

product \:  \: of \:  \: zeroes =  \frac{c}{a}  

5 \times ( - 5) =  \frac{ - 75}{3}  

- 25 =  - 25

Step-by-step explanation: