Question

1. Find the zeroes of the quadratic polynomial x²-7x+12​

Answer 1

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$\implies \: \: {x}^{2} - 7x + 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \: \: {x}^{2} - 3x - 4x + 12 \: \: \: \: \\ \\ \implies \: \: x(x - 3) - 4(x - 3) \: \\ \\ \implies \: \: (x - 3)(x - 4) \: \: \: \: \: \: \: \: \: \: \:$

let (x – 3) (x –4) = 0

So the zeros of the polynomial = 3 and 4