Question

1. Find the zeroes of x2-2x-8​

Answer 1

a*c=-8x²

IbI = 2x

p(x)=x²-2x-8

ײ-4x+2x-8

x(x-4)+2(x-4)

(x-4)(x+2)

x-4=0 & x+2=0

x=4 x=-2

Zeroes are 4 and -2.

Hope it helps

Answer 2

Answer:

4 and 2 are tow zeroes

Step-by-step explanation:

4 and -2 are the two zeroes of the polynomial X²-2X-8.