Question

1) find the zeroes or x²-2x-8 Quadratic polynomial and
verify the relationship between the zeroes and
coefficents.​

Answer 1

Step-by-step explanation:

=x^2-2x-8

by middle term splitting,

=x^2-4x+2x-8

=x(x-4)+2(x-4)

=(x-4)(x+2)

so the zeroes of polynomial=4 and -2

verification of relationship between zeroes and coefficients,

sum of zeroes =-b/a

4+(-2)=-(-2)/1

2=2

product of zeroes=c/a

4×(-2)=-8

-8=-8

hope it helps

Answer 2

Answer:

$x {}^{2} - 2x - 8 \\ x {}^{2} - 4x + 2x - 8 \\ x(x - 4) + 2(x - 4) \\ (x - 4)(x + 2) \\ x - 4 = 0 \\ x = 4 \\ x + 2 = 0 \\ x = - 2$

4 and -2 are the zeros of given quadratic equation .

here, a =1 b = -2 c = -8

relationship between coefficient and zeros

sum of zeros = -b/a

4+(-2)= -(-2)/1

2 = 2

product of zeros = c/ a

4×(-2) = -8/1

-8 = -8