Question

1) Find the zeros et the Quadratic polynomial
6x²-3-7x​

Answer 1

Step-by-step explanation:

$6x {}^{2} - 7x - 3 \\ 6x {}^{2} - 9x + 2x - 3 \\ 3x(2x - 3) + 1(2x - 3) \\ (3x + 1)(2x - 3)$

$x = \frac{ - 1}{3} or \: x = \frac{3}{2}$