Question

1. find the zeros of the quadratic polynomial 6x^2 - 3 - 7x *


1. -1/3 and 3/2

2. -3/2 and 1/3

3. 1/2 and 3/2

4. -1/2 and -3/2

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Answer 1

Answer:

1.-1/3 and 3/2

Step-by-step explanation:

6x^2-3-7x

=6x^2-7x-3

=6x^2-(9-2)x-3

=6x^2-9x-2x-3

=3x(2x-3)+1(2x-3)

=(3x+1)(2x-3)

Either,

3x+1=0

3x=-1

x=-1/3

Or,

2x-3=0

2x=3

x=3/2

Answer 2

Step-by-step explanation:

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