Question

1. Find three consecutive even integers so that the sum of the smallest and bigest is 36.​

Answer 1

Answer:

The three consecutive integers are 16, 18 and 20

Step-by-step explanation:

Let the three consecutive even integers be 2n, 2n +2 and 2n + 4

The sum of the smallest and the biggest is 36

i.e. 2n + 2n + 4 = 36

4n + 4 = 36

4n = 32

n = 8

So,

The 1st number = 2n = 2 × 8 = 16

The 2nd number = 2n + 2 = 2 × 8 + 2 = 18

The 3rd number = 2n + 4 = 2 × 8 + 4 = 20

Answer 2

Answer:

16 , 18 , 20

Step-by-step explanation:

given data,

let first number = x

then second and third numbers will be x+2 and x+4 respectivly,

and x+x+4 = 36 ,

=2x = 36-4

=2x =32

x = 32/2

x = 16

so the first number is 16

secong number will be 16+2 = 18

third number will be 16+4 = 20

check = 16+20 = 36

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