Question

1. Find three different solutions of the each of the following equations.
1 3x+4y=7
ii) y=6x
iii) 2x - y=7
iv) 13x - 12y = 25 v) 10x + lly=21 vi) x+y=0​

Answer 1

❥The given equation is:

3x + 4y = 7

We take x = 1, y = 1

Then, 3 (1) + 4 (1) = 3 + 4 = 7

Thus, x = 1, y = 1 be a solution

Let, x = 0

Then,

3 (0) + 4y = 7

or, 4y = 7

or, y = 7/4

Thus, a solution be

x = 0, y = 7/4

Let, y = 0

Then,

3x + 4 (0) = 7

or, 3x = 7

or, x = 7/3

Thus, another solution be

x = 7/3, y = 0

Hence, the three solutions are

➤x = 1, y = 1

➤x = 7/3, y = 0

➤x = 0, y = 7/4.

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❥sᴏʟᴠᴇ ʙʏ ᴍʏsᴇʟғ♡

❥ɴɪᴄᴇ ᴅᴀʏ

Answer 2

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