Question

1. Find three different solutions of the each of the following equations,
1) 3x+4y= 7
ii) y 6x
fii) 2x - y - 7
iv) 13x - 12y = 25 v) 10x +11y = 21 vi) x+y=0​

Answer 1

Step-by-step explanation:

Given that:-

1)3x+4y=7

Put x=0 then

3(0)+4y=7

=>0+4y=7

=>4y=7

=>y=7/4

solution=(0,7/4)

Put y=0 then

=>3x+4(0)=7

=>3x+0=7

=>3x=7

=>x=7/3

Solution=(7/3,0)

Put x=5 then

=>3(5)+4y=7

=>15+4y=7

=>4y=7-15

=>4y=-8

=>y=-8/4

=>y=-2

Solution=(5,-2)

vi)Given equation is x+y=0

put x=0 then

=>0+y=0

=>y=0

solution=(0,0)

put y=1 then

=>x+1=0

=>x=-1

solution=(-1,1)

put x=2 then

=>2+y=0

=>y=-2

solution=(2,-2)