1.Find two consecutive positive integers,the sum of whose squares is 365.
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Answer:
numbers are 13 and 14
Step-by-step explanation:
Let 2 consecutive number be x and x+1
x² + (x+1)² = 365
x² + x² + 1 + 2x = 365
2x² + 2x - 364 = 0
x² + x - 182 = 0
x = 13 and -14
So, numbers are 13 and 14
I hope it helps you
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