(1 Find two numbers whose sum is 27 and product is 182.
(2 The altitude of a right triangle is 7cm less than its base. If the hypotenuse is 13cm, find the other two sides.
(3 Solve the problems given in Example 1.
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Answer:
- Let x and y be two numbers
Given, x+y=27 ............(1)
and xy=182 .............(2)
From (1), we get x=27−y
Put x=27−y in (2) we get,
(27−y)y=182⇒27y−y2=182⇒y2−27y+182=0
⇒(y−14)(y−13)=0
⇒y=14 or y=13
∴ if y=14 then x=13 and if y=13 then x=14
Two numbers are 13 and 14
- Let x be the base of the triangle, then the altitude will be (x−7).
By Pythagoras theorem,
x2+(x−7)2=(13)2
2x2−14x+49−169=0
2x2−14x−120=0
x2−7x−60=0
x2−12x+5x−60=0
(x−12)(x+5)=0
x=12,x=−5
Since the side of the triangle cannot be negative, so the base of the triangle is 12cm and the altitude of the triangle will be 12−7=5cm.
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