Question

1. Find using identity: {3x-y-4} {3x-y+5} 2. Factorise a^3 -b^3+1+3ab
Urgent

Answer 1

Answer:

hope it helps....

Step-by-step explanation:

1)(3x−y−4)(3x−y+5)

=(3x+−y+−4)(3x+−y+5)

=(3x)(3x)+(3x)(−y)+(3x)(5)+(−y)(3x)+(−y)(−y)+(−y)(5)+(−4)(3x)+(−4)(−y)+(−4)(5)

=9x2−3xy+15x−3xy+y2−5y−12x+4y−20

=9x2−6xy+y2+3x−y−20

2)a3−b3+1+3ab

=a3+−b3+1+3ab

Answer:

=a3−b3+3ab+1