1. Find using identity: {3x-y-4} {3x-y+5} 2. Factorise a^3 -b^3+1+3ab
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Answer:
hope it helps....
Step-by-step explanation:
1)(3x−y−4)(3x−y+5)
=(3x+−y+−4)(3x+−y+5)
=(3x)(3x)+(3x)(−y)+(3x)(5)+(−y)(3x)+(−y)(−y)+(−y)(5)+(−4)(3x)+(−4)(−y)+(−4)(5)
=9x2−3xy+15x−3xy+y2−5y−12x+4y−20
=9x2−6xy+y2+3x−y−20
2)a3−b3+1+3ab
=a3+−b3+1+3ab
Answer:
=a3−b3+3ab+1
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