Question

1) Find value of k for which
x=a is a solution of
x² - x (atb)+k=0​

Answer 1

Answer:

k= -ab

please write question clearly

Answer 2

Answer:

K= ab

Step-by-step explanation:

one of the root is x= a

2. ${x}^{2} - x(a + b) + k = 0 \\ {a }^{2} - a(a + b) + k = 0 \\ {a}^{2} - {a}^{2} - ab + k = 0 \\ - ab + k = 0 \\ k = ab$