Question

1) find value of (x²)⁰ + 1^x
2)find value of 1^m+5 - x⁰​

Answer 1

Answer:

56_:&+75:&6-)&75:68y

Answer 2

Answer:

For example

Step-by-step explanation:

1)if x=12

x^2=12^2=144.

then,

x^2-1=144-1=143

2)There are 3 values for x:

If you take it as (x+1)/x = 3, then

x+1 = 3x, or

2x = 1, or

x = 0.5

Check: (0.5+1)/0.5 = 3. Correct

If you take it as x + (1/x) = 3, then

x^2–3x+1 = 0

x1 = [3+(9-4)^0.5]/2 = [3+5^0.5]/2 = 2.618033989.

x2 = [3-(9-4)^0.5]/2 = [3–5^0.5]/2 = 0.381966011.

Check: x1+(1/x1) = 2.618033989+(1/2.618033989) = 3. Correct.

x2+(1/x2) = 0.381966011+(1/0.381966011) = 3. Correct.

x1 = 2.618033989.

x2 = 0.381966011.