Question

1. Find zeroes of polynomial x2-3x.
2. Solve x/3 = y/2 - 7​

Answer 1

Answer:

Question:-

Find zeroes of polynomial x²-3x.

Solution:-

⟹ x²-3x

⟹ x(x-3)

⟹(x-3)(x+1)

⟹ zeros

x=3

x=(-1)

Answer 2

Answer:

1)$x^{2} -3x$ = 0

     x(x-3) = 0

     here x or x-3 must be zero [because the product is zero}

  x = 3 ,0

2)x/3 = y/2-7

  x/3-y/2=-7

  (2x-3y)/6= -7

  2x-3y   = -42

{that is the answer we cant find the exact value of x and y}